-x^2+30x+4x=-2x^2+14x+6

Solution for -x^2+30x+4x=-2x^2+14x+6 equation:

-x^2+30x+4x=-2x^2+14x+6

We move all terms to the left:

-x^2+30x+4x-(-2x^2+14x+6)=0

We add all the numbers together, and all the variables

-1x^2-(-2x^2+14x+6)+34x=0

We get rid of parentheses

-1x^2+2x^2-14x+34x-6=0

We add all the numbers together, and all the variables

x^2+20x-6=0

a = 1; b = 20; c = -6;
Δ = b2-4ac
Δ = 202-4·1·(-6)
Δ = 424
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{424}=\sqrt{4*106}=\sqrt{4}*\sqrt{106}=2\sqrt{106}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-2\sqrt{106}}{2*1}=\frac{-20-2\sqrt{106}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+2\sqrt{106}}{2*1}=\frac{-20+2\sqrt{106}}{2}
$